Question 854111
Is this it?
{{{root( 4, x^24z^28 / 81 ) }}}
If so:
{{{root( 4, x^24z^28 / 81 ) = ( x^24*z^28 / 3^4 )^(1/4) }}}
{{{ ( x^24*z^28 )^(1/4) / (( 3^4)^(1/4) ) }}}
{{{ ( x^(24/4)*z^(28/4) ) / 3^(4/4) }}}
{{{ ( x^6 * z^7 ) / 3 }}}
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The only rules used here are:
{{{ ( a^b )^c = a^(b*c) }}}
and
{{{ ( a/b)^c = a^c *( 1/b)^c }}}