Question 854012
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Hi,
 x^2-6x-8y+49=0
8y = (x-3)^2 + 40
 y = (1/8)(x-3)^2 + 5   Parabola opening right, y = 5, line of symmetry
V(3,5),  {{{1/8 = 1/(4p)}}}, {{{ highlight_green(p = 2)}}}, Focus(5,5), Directrix x = 1