Question 853958
<pre><font face = "Tohoma" size = 3 color = "indigo"><b> 
Hi,
{{{log(9, (x+6)/2x)}}} = 0
      9^0 = 1 = (x+6)/2x
            2x = x+6
             x = 6
*[tex \large\ \ nlog_bx = log_b(x^n) ]
*[tex \large\ \ log_bx + log_by = log_b(xy) ]
*[tex \large\ \ log_bx - log_by = log_b(x/y) ]  Applied
*[tex \large\ \ log_b1 = 0]
*[tex \large\ \ log_bb = 1]
*[tex \large\ \ log_b(x) \ = \ y \ \ \Rightarrow\ \ b^y = x]  Applied