Question 853848
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Hi,
parabola with the vertex (2,4)and foucs (5,4)
Opening Right, line of symmetry  y = 4
Sketch IT
{{{x=a(y-4)^2 + 2}}}  (5-2) = 3  a = {{{1/(4*3) = a = 1/12)}}}
{{{x=(1/12)(y-4)^2 + 2}}} 
the vertex form of a Parabola opening right(a>0) or left(a<0), {{{x=a(y-k)^2 +h}}}
 where(h,k) is the vertex and  y = k  is the Line of Symmetry
{{{drawing(300,300,   -10,10,-10,12, 
 grid(1),
circle(2, 4,0.4),
circle(5, 4,0.4),
circle(5, -2,0.4),
circle(5, 10,0.4),
line(5,-2,5,10),
graph( 300, 300, -10,10,-10,12,0,4, sqrt(12(x-2)) + 4,-sqrt(12(x-2)) + 4 ))}}}