Question 853739
Notice that if we have expressions of the form {{{x^2 - y^2}}}
factor to (x - y)(x + y).
{{{ 10000x^2-64=0 }}} can be written as {{{(100x)^2 - 8^2 = 0}}}
 {{{(100x - 8)(100x + 8)=0}}}
Either 100x - 8 = 0 or 100x + 8 = 0
Take 100x - 8 = 0 first.
add 8 to each side
100x = 8
divide each side by 100
x = 8/100
Now 100x + 8 = 0
add -8 to each side
100x = -8
divide each side by 100
x = -8/100