Question 853816
1.)A ball is thrown upward with an initial velocity 60m/sec. The speed of the ball decreases uniformly with time and after 3 secs its velocity is 30.6m/sec.

a.)Determine the equation relating the velocity of the ball and time
acceleration = change in speed/time
a = (30.6 - 60)/3
a = - 9.8 m/sec/sec (negative since it's decreasing)
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v = 60 + a*t
v = 60 - 9.8t
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b.)Draw the line given by this equation
It's a straight line thru the 2 points (0,60) and (3,30.6)
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c.)Determine the time at which the velocity of the ball is zero
v = 60 + at
v = 60 - 9.8t = 0
t = 60/9.8
t =~ 6.122 seconds