Question 853803
Looks like you've lost a couple of terms and you could simplify further by multiplying your constants.
Let's simplify first then divide.
{{{(3^-2*(x-1)^4*(xy^2)^3*z^5)=(1/9)*(x-1)^4*x^3*y^6*z^5}}}
{{{(9x^6)^2*y^4*(x-1)^(-2)z^(-1)=81*x^12*y^4*(x-1)^(-2)*z^(-1)}}}
Putting it together,
{{{(3^-2*(x-1)^4*(xy^2)^3*z^5)/((9x^6)^2*y^4*(x-1)^(-2)z^(-1))=((1/9)*(x-1)^4*x^3*y^6*z^5)/(81*x^12*y^4*(x-1)^(-2)*z^(-1))}}}
{{{(3^-2*(x-1)^4*(xy^2)^3*z^5)/((9x^6)^2*y^4*(x-1)^(-2)z^(-1))=((1/729)*(x-1)^4*x^3*y^6*z^5)*x^(-12)*y^(-4)*(x-1)^(2)*z^(1))}}}
{{{(3^-2*(x-1)^4*(xy^2)^3*z^5)/((9x^6)^2*y^4*(x-1)^(-2)z^(-1))=(1/729)*(x-1)^(4+2)*x^(3-12)*y^(6-4)*z^(5+1)}}}
{{{(3^-2*(x-1)^4*(xy^2)^3*z^5)/((9x^6)^2*y^4*(x-1)^(-2)z^(-1))=(1/729)*(x-1)^(6)*x^(-9)*y^(2)*z^(6)}}}
{{{(3^-2*(x-1)^4*(xy^2)^3*z^5)/((9x^6)^2*y^4*(x-1)^(-2)z^(-1))=highlight(((x-1)^(6)*y^(2)*z^(6))/(729*x^9))}}}