Question 853742
{{{ 9x^2-8=-34x }}}


{{{ 9x^2+34x-8=0 }}}

we can solve this by squaring method

divide by 9

{{{x^2 +(34/9)x = 8/9}}}

Third term = (1/2* coefficient of second term )^2

= {{{((1/2) * (34/9))^2}}}

={{{(17/9)^2}}}

={{{x^2 +(34/9)x+(17/9)^2 = 8/9 +(17/9)^2}}}

={{{(x+(17/9))^2= (8/9) +(17/9)^2}}}

{{{x+(17/9)= sqrt(361/81)}}}

x+17/9 = +/- 19/9

x=-17/9 -19/9 
=-36/9
=-4

OR
x=-17/9 +19/9
x=2/9

x=2/9 OR -4