Question 853372
{{{int((2x-7)^3,dx)}}}
Use a substitution,
{{{u=2x-7}}}
{{{du=2dx}}}
{{{dx=(1/2)du}}}
{{{int((2x-7)^3,dx)=int((1/2)u^3,du)}}}
{{{int((2x-7)^3,dx)=(1/2)*int(u^3,du)}}}
{{{int((2x-7)^3,dx)=(1/2)*(u^4/4)}}}
{{{int((2x-7)^3,dx)=u^4/8+C}}}
{{{int((2x-7)^3,dx)=(1/8)*(2x-7)^4+C)}}}