Question 852684
It appears that we have a semicircle over a square.
The area of the square is 16*16 = 256
The area of the semicircle is {{{(1/2)*(pi)(16/2)^2}}}
since the radius of the semicircle is 1/2 of the diameter of 16.
{{{(1/2)*(pi)(16/2)^2}}} =
{{{(1/2)*(pi)(8)^2}}}
{{{(1/2)*(pi)*64}}}
{{{(pi)*32}}}
So the total area is {{{256 + 32(pi)}}}