<PRE><B>Question 853282</B>
The ball falls first from 10 feet

then rises again

Number of falls = number of rises + 10 feet 

It is a geometric series

a= 4 
r= 2/5
n= 4

Sn = {{{(a1(1-r^n))/(1-r)}}}

Substitute the values 
we get Sn = 6 49/99
Distance during rises

Distance during falls = 6 49/99 + 10 = 16 49/99 

Total = 6 49/99 + 16 49/99 = 22 98/99 

Option (d)</PRE>