Question 71905
{{{(z+7/9)+ 1}}} = {{{((2z+1)/6)/18}}}
:
{{{(z+7/9+1)*18=2z+1/6/18*18}}}
Right here you should have
{{{18z+126/9+18=(2z+1)/6}}}
{{{18z+14+18=(2z+1)/6}}}
{{{18z+32=(2z+1)/6}}}
:
Multiply by 6:
108z + 192 = 2z + 1
:
108z - 2z = 1 - 192
106z = -191
z = -191/106
z = -1.8