Question 853276
P is the point (-1,3) . Q is the point (2,-1) .
Find the equation of line PQ.
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Equation of line: y=mx+b, m=slope, b=y-intercept
slope=∆y/∆x=(3-(-1))/(-1-2)=4/-3=-4/3
equation: 
y=-4x/3+b
solve for b using coordinates of one of given points(2,-1)
-1=-4*2/3+b
b=5/3
equation: {{{y=-4x/3+5/3}}}