Question 853239
Let the long leg of this right triangle be "x"
Then you will have the short leg is "x-5" and the hypotenuse is "x+5"
Use Pythagorean Theorem, you will have:
{{{(x-5)^2 + x^2 = (x+5)^2}}}
{{{x^2 -10x + 25 + x^2 = x^2 + 10x + 25}}}
{{{2x^2 - 10x + 25 = x^2 + 10x + 25}}}
{{{x^2 - 20x = 0}}}
{{{x(x-20) = 0}}}
x = 0 or x = 20
But since a side of a triangle can't be 0, x=20
So you have the long leg of the triangle is 20
The short leg will be 20-5 = 15
The hypotenuse will be 20+5 = 25
TA-DAH
:D