Question 853046
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Hi,
x+y+2z= 11 and 
x+y+3z=14 
x+y+2z= 11 and
<u>-x-y-3z=-14</u>   |Subtract 2nd from first to eliminate x & y
      -z = -3
     {{{ highlight_green(z = 3)}}}
x+y+3z=14 and 
x+2y-z=5
x+y+9=14 and    |Substitute z = 3
x+2y-3=5
x+y = 5 and 
x+2y = 8
x+y = 5 and 
<u>-x-2y = -8</u>    |Subtract 2nd from first to eliminate x
      -y = -3
      {{{ highlight_green(y = 3)}}}  and x+y+2z= 11 &#8658; x + 3 + 6 = 11 {{{ highlight_green(x = 2)}}} 
(2, 3, 3) the solution for this system