Question 853000
Use the following fact if x=y then {{{e^x = e^y}}}.  Also use the fact that {{{e^lnx}}}=x.  Also use {{{e^0 = 1}}}<P>
Raise e to the power of each side of the equation.  <P>
{{{e^(lnlnln(x+6)) = e^0}}}<P>
ln(ln(x+6) = 1<P>
{{{e^lnln(x+6) = e^1}}}<P>
ln(x+6) = e<P>
{{{e^ln(x+6) = e^e}}}<P>
{{{x+6 = e^e}}}<P>
{{{x=e^e - 6 }}} = approximately 9.154