Question 852985
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Hi,
4^(log2(3+x)) = 2x^2+8x+10  
(2^2)^(log2(3+x)) = 2x^2+8x+10  
(2)^(2log2(3+x)) =2x^2+8x+10  
 (2)^(log2(3+x)^2) = 2x^2+8x+10     {{{ 2^(log(2,V)) = V}}}
        (3+x)^2) = 2x^2+8x+10  
     9 + 6x + x^2 = 2x^2+8x+10  
          x^2 + 2x + 1 = 0  Factor
          (x+1)(x+1) = 0 ,  x = -1