Question 852935
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Hi,
2% &#8658; z = NORMSINV(.02) = Z = -2.0538
mean of	38 and standard deviation of 5.9. 
 -2.0538 = (X-38)/5.9
{{{5.9(-2.0538) + 38 }}}= 25.88  0r 26  rounded Up
2% of employees are younger than 26