Question 852806
find three consecutive odd positive integers such that the sum of all three is 26 less than the product of the first and second integers.  What is the formula to set this up?
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1st: 2x-1
2nd: 2x+1
3rd: 2x+3
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Equation:
6x+3 < 4x^2-1-26
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4x^2 - 30 > 0
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x^2 > 15/2
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x > (sqrt(30))/2
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OR
x > (sqrt(30))/2
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Cheers,
Stan H.
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