Question 852775
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Hi,
p = .06, n = 14
Using TI ****(highly recommended for cumulative probabilities
P(x &#8804;  2) = binomcdf(14, .06, 2)
Or
Using {{{P (x)= highlight_green(nCx)(p^x)(q)^(n-x) }}} 
P(x &#8804; 2)= P(0)+ P(1) + P(2) = .94^14 + 14(.06)^1(.94)^13 + 91(.06)^2(.94)^12