Question 852777
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Hi,
p = .07, n = 19
Using TI ****(highly recommended for cumulative probabilities
P(x &#8805; 2) = 1 – binomcdf(19, .07, 1)
Or
Using {{{P (x)= nCx(p^x)(q)^(n-x) }}} 
P(x &#8805; 2)= 1 -P(0) - P(1)= 1 - .93^19 - 19(.07)^1(.93)^18