Question 852586
Suppose that you are in a class of 33 students and it is assumed that approximately 17% of the population is left handed.
a) Compute the probability that exactly five students are left handed
P(x=5) = 33C5(0.17)^5(0.83)^28 = binompdf(33,0.17,5) = 0.1827
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b) compute the probability that at most four students are left handed
P(0<= x <=4) = binomcdf(33,0.17,4) =  0.3178 
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c) compute the probability that at least six students are left handed
P(17<= x <=33) = 1 - binomcdf(33,0.17,16) = 0.00000596...
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Cheers,
Stan H.
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