Question 71835
The perimeter of a rectangular writing pad is 28 inches.  The length is 1 inch less than twice the width.  What did I do wrong in setting the problem up?
            P= 2l + 2w, length is 2x-1
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That's good so far.
width = x and length = 2x-1

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Now substitute to get:
28 = 2(2x-1)+2x
Then you can solve for x and for 2x-1.
cheers,
Stan H.