Question 852488
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Hi,
Using TI P(x &#8805; 1) The syntax is 1 – binomcdf(n, p, largest x-value).
p = .65,  n = 5
P(x &#8805; 1) =  1 – binomcdf(5,.65,0)
0r using {{{P (x)= nCx(p^x)(q)^(n-x) }}} where p and q are the probabilities of success and failure respectively. 
P(x &#8805; 1) = 1 - P(0)= 1 - (.35)^5