Question 71803
1st:  r-3p=1
2nd:  6r-p=6
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Solve 1st for r: r=3p+1
Substitute that into 2nd to get:
6(3p+1)-p=6
18p+6-p=6
18p-p=0
17p=0
p=0
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Substitute that into r=3p+1
r=3*0+1
r=1
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Solution: r=1; p=0
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Cheers,
Stan H.