Question 852054
log1 to the base e + 3log10 to the base 10 - log32 to the base 2
{{{ln(1) + 3log(10) - log(2,32)}}}
the nat log of 1 = 0 so we can ignore that.
{{{3log(10) - log(2,32)}}}
{{{log(10^3) - log(2,32)}}}
{{{log(1000) - log(2,32)}}}
we know the log of 1000 is 3
{{{3 - log(2,32)}}}
we know that 32 = 2^5, therefore
3 - 5 = -2