Question 852239
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Hi,
{{{x=8(y-5)^2 +2}}} 
sketch IT Parabola opening right a < 0
the vertex form of a Parabola opening right(a>0) or left(a<0), {{{x=a(y-k)^2 +h}}}
 where(h,k) is the vertex and  y = k  is the Line of Symmetry 
{{{x=8(y-5)^2 +2}}}  V(2,5)
{{{drawing(300,300, -10,10,-10,10,   grid(1), blue(line(0,20,0,-20)) ,
circle(2,5,0.3),
graph( 300, 300, -10,10,-10,10,    0 ,5, sqrt((1/8)(x-2))+5, -sqrt((1/8)(x-2))+5 ))}}}