Question 852169
The slope of the tangent is the value of the derivative at that point.
{{{y=x^2/19}}}
{{{dy/dx=(2/19)x}}}
At {{{x=4}}},{{{m=dy/dx=(2/19)(4)=8/19}}}
{{{y=(8/19)x+b}}}
Use the point (4, 16/19) to determine {{{b}}}.
{{{16/19=(8/19)4+b}}}
{{{16/19=32/19+b}}}
{{{b=-16/19}}}
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{{{y=(8/19)x-16/19}}}
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{{{drawing(300,300,-2,8,-5,5,circle(4,16/19,0.2),grid(1),graph(300,300,-2,8,-5,5,x^2/19,(8/19)x-16/19))}}}