Question 851752
{{{drawing(300,300,-2,10,-10,100,grid(1),
circle(1,15,0.2),
circle(2,16,0.2),
circle(3,31,0.2),
circle(4,41,0.2),
circle(5,51,0.2),
circle(6,88,0.2),
circle(7,98,0.2))}}}
Yes, an exponential model is a good fit.
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{{{y=9.95e^0.34x}}}
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{{{R^2=0.9713}}}
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{{{drawing(300,300,-2,10,-10,100,grid(1),
circle(1,15,0.2),
circle(2,16,0.2),
circle(3,31,0.2),
circle(4,41,0.2),
circle(5,51,0.2),
circle(6,88,0.2),
circle(7,98,0.2),graph(300,300,-2,10,-10,100,9.9518*(2.718^(0.3408*x))))}}}