Question 852124
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Hi,
Note: The probability of x successes in n trials is: 
P (x)= {{{nCx (p^x)(q)^(n-x)}}}  where p and q are the probabilities of success and failure respectively. 
In this case p = 1/6 & q = 5/6  n = 8
*[tex \LARGE{{8}\choose{3}}] = {{{(n!)/x!(n - x)! = 8*7*6/(2*3) = 56}}} 
P(x=3) ={{{ 56(1/6)^3(5/6)^5 = .1042}}}  You had just not used the 'combination factor' of 56