Question 852110
Inverse functions you mean.
{{{y=(x-1)/(x+2)}}}
Interchange x and y and solve for the new y, this is the inverse.
{{{x=(y-1)/(y+2)}}}
{{{x(y+2)=y-1}}}
{{{xy+2x=y-1}}}
{{{xy-y=-2x-1}}}
{{{y(x-1)=-2x-1}}}
{{{highlight(y=(-2x-1)/(x-1))}}}