Question 852092
{{{((3-7i)/4i)*((4i)/(4i))=(12i-28i^2)/(16i^2)}}}
{{{((3-7i)/4i)*((4i)/(4i))=(12i-28(-1))/(16(-1))}}}
{{{((3-7i)/4i)*((4i)/(4i))=(12i+28)/(-16)}}}
{{{((3-7i)/4i)*((4i)/(4i))=-((3i+7))/(4)}}}
{{{((3-7i)/4i)*((4i)/(4i))=-(7/4+(3/4)i)}}}