<PRE><B>Question 852011</B>
I really researched your currencies, I&#39;m not familiar with it.

Since a dime is worth 10 cents or $.10
and a nickel is 5 cents or $.05

$1.95 is equal to 195 cents right?

So Let;
d - number of dimes
n - number of nickel

(1) d+n=23     this is our first equation
(2) 10d+5n=195 this is our second equation since the value of dime is 10 and nickel is 5


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Multiply both sides of (1) by 10 and subtract (1) from (2) (We use 10 in order to get rid of d)
-------------
(2) 10d+ 5n=195
(1) 10d+10n=230

Subtract (1) from (2)
(2)  10d+ 5n=195
(1)- 10d+10n=230
This is equal to
       -5n=-35
         n=7

Since n=7,

(1) d+n = 23
(1) d+7 = 23
It follows that,
(1) d=16

It means there are 7 nickels and 16 dimes!

Try to solve it if you get 195 in (2)

(2) 10d+5n=195 Substitute
(2) 10(16)+5(7)=195
(2) 160+35=195

Super okay!

Hope that helps!!
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