Question 852002
Let:

x   -be the number
x+1 -be the 2nd number
x+2 -be the 3rd number
x+3 -be the fourth number

You know since they are consecutive :)

(x)(x+1)(x+2)(x+3)=15000

{{{(x^2+x)(x^2+5x+6)=15000}}}
{{{x^4+6x^3+11x^2+6x=15000}}}
{{{(1/x)(x^4+6x^3+11x^2+6x)=(1/x)15000}}}
{{{x^3+6x^2+11x+6=(15000/x)}}}

Find x you know. I'm sorry it's just hard to type I'll be late for my examinations wish me luck! ;)