Question 851916
Hello.  You need to rewrite each fraction without the 3 and without the 2 in the numerators.  When you do this, you will end up with:


{{{((x+3)^2)/(5/3)-(y+1)^2/(5/2)=1}}}


However, the denominators are fractions and are not perfect squares. I am unsure how they came up with {{{((x+3)^2)/2-(y+1)^2/3=1}}}, unless I'm missing something...