Question 851772
Hello,

2x - 3 < x + 2 &#8804; 3x + 5


1.  Separate these into two different inequalities:


2x - 3 < x + 2  AND  x + 2 &#8804; 3x + 5


2.  Solve for x in each inequality:


2x - 3 < x + 2 -----> x < 5


x + 2 &#8804; 3x + 5 ----->  -3 &#8804; 2x -----> -3/2 &#8804; x


We now know that x must be less than 5 and greater than -3/2.  So, 


-3/2 &#8804; x < 5  which is your final answer.