Question 851664
{{{dx/dy=xy-x}}}
{{{dx/dy=x(y-1)}}}
{{{dx/x=(y-1)dy}}}
{{{log((x))=y^2-y+C}}}
When {{{y=2}}}, {{{x=1}}}
{{{log((1))=2^2/2-2+C}}}
{{{0=2-2+C}}}
{{{C=0}}}
{{{log((x))=y^2/2-y}}}