Question 851565
S = ½(2a1 + d(n-1))n
44 = ½(2a + d(10))11,
8=2a+10d

9 = (2a + d(21))
9=2a+21d,
8=2a+10d
9=21d
8=10d
1=11d
1/11=d
8=2a+10d
8=2a+10/11

4=a+5/11
39/11=a
first term is 39/11
difference is 10/11
check
44 = ½(2a + d(10))11
44=1/2(2*39/11+10/11)*11
ok