Question 851247
{{{f(x)=(x+3)/(x^2-5x-24)=(x+3)/((x+3)(x-8))}}}


The factor of 1 as {{{(x+3)/(x+3)}}}  is undefined at x=-3, so that would be a hole in the graph.  Division by zero is impossible.


The denominator will be undefined as will be the function when x=8; again because the denominator must not be zero, because division by zero is impossible.  This will make x=8 a vertical asymptote.