Question 851241
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Hi,
1/x^2+3x+2 + x/x+2 = 1/2
{{{1/(x+2)(x+1) + x/(x+2) = 1/2}}}   |Multiplying thru by {{{ highlight_green(2(x+1)(x+2))}}} so as all denominators = 1
 2 + 2x(x+1) = (x+1)(x+2)
 2 + 2x^2+ 2x = x^2 + 3x + 2
     x^2 - x = 0
    x(x-1) = 0,  x = 0   0r  x = -1