Question 851156
One year ago,the father was 8 times as old as his son.Now his age is square of the son's age.Find their present ages.
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F = S^2
(F-1) = 8*(S - 1) --> F = 8S - 7
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S^2 = 8S - 7
{{{S^2 - 8S + 7 = 0}}}
(S - 1)*(S - 7) = 0
S = 1 --> zero one year ago.
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S = 7
F = 49