Question 851006
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What two numbers have a product that is twice their sum and have a difference of 2

Solution:
Let one number be x. Then the other is x + 2.
Sum of the numbers = {{{x + x + 2 = 2*x + 2}}}
Product = {{{x*(x + 2) = x^2 + 2*x}}}
Since product is twice the sum,

{{{x^2 + 2*x = 2(2*x + 2) = 4*x + 4}}}

{{{x^2 - 2*x - 4 = 0}}}

Solution below:

*[invoke quadratic "x", 1, -2, -4 ]

The 2 numbers are approximately {{{highlight(3.23)}}} and highlight{{{highlight(5.23)}}}

Hope this helps :)

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