Question 851070
The leading term tells you the graph opens upward and so vertex is a minimum, and you should find the quadratic factorable.

{{{y=x^2+x-6=(x-2)(x+3)}}}
zeros are x=2 and x=-3.

y is negative between x= 2  and x=-3, but positive outside that interval.

The axis of symmetry is {{{x=(2+(-3))/2=-1/2}}}


{{{graph(300,300,-10,10,-13,13,x^2+x-6)}}}