Question 71591
0.3^(1+x)= 1.7^(2x-1)

Take the log of both sides to get:

(1+x) log 0.3  = (2x-1) log 1.7

log0.3 + x(log0.3) = 2x(log1.7) -log1.7
x(log0.3-2log1.7)= -(log0.3+log1.7)

x= -(log0.3+log1.7)/(log0.3-2log1.7)

x= 0.2924../-0.98378...
x= -0.2972522699...
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Cheers,
Stan H.