Question 850859
1.{{{x- 2y + z = 4}}}
2.{{{y + 6z =-1}}}
3.{{{z = 2}}}
Back substitute from eq. 3 into eq. 2,
{{{y+6(2)=-1}}}
{{{y+12=-1}}}
{{{y=-13}}}
Now into eq. 1,
{{{x-2(-13)+2=4}}}
{{{x+26+2=4}}}
{{{x=-24}}}