Question 71669
4y to the sixth minus 14y to the fifth minus 144y to the third equals 0
4y^6-14y^5-144y^3=0
Factor out 2y^3 to get:
2y^3(2y^3-7y^2-72)=0
y=0 with multiplicity 3
I graphed the cubic and found a root at approximately y=-4.9620881
The other two zeroes may be complex numbers:not sure.
Cheers,
Stan H.