Question 850837
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Hi,
Note: shortlisted 2/3 of the time 
'short listed' ...  more family than friends in the group of 3
A.  2C2*5C1 are the 5 ways there are more family than friends:  
P(shortlisted) = 2C2*5C1/7C3 =  5/35 = 1/7
P(shortlisted 2/3 of the time ) =  (2/3)(1/7)  =  2/21 = .0952
b. P = {{{4C2*3C2/(7C3)}}}