Question 850669
{{{(cot(4x))^2 = 3}}}
{{{1/tan(4x)=0 +- sqrt(3)}}}
{{{tan(4x)=0 +- 1/sqrt(3)}}}
{{{4x=0 +- (1/6)pi}}}
and 
{{{4x= 0 +- (5/6)pi}}}
.
.
{{{x=0 +- (1/24)pi}}}
and
{{{x=0 +- (5/24)pi}}}