Question 850419
Since this is the area {{{4z^2-36z+81}}} and finding for the area of square is
{{{A = s^2}}} where s is the side, the perimeter P=4s.

In the area {{{4z^2-36z+81}}}, we can factor it to

{{{4z^2-36z+81 = (2z-9)(2z-9)}}}

Therefore {{{4z^2-36z+81 = (2z-9)^2}}} ans s = 2z-9

And the perimeter

P= 4(2z-9)

If z=10, substitute

P = 4(2(10)-9)
P = 4(20-9)
P = 4(11)
P = 44 feet :)

Hope that helps.

#rda33