Question 850312
That asks, find x for y=0.


{{{2(-4(x-1))^3=y=0}}}
{{{((-4)(x-1))^3=0}}}
{{{(-4x+1)^3=0}}},  only one binomial factor.
{{{-4x+1=0}}}
{{{4x-1=0}}}
{{{4x=1}}}
{{{x=1/4}}}